I want to differentially feed the twin line. One microstrip line shall have a positive voltage and ground at the reference. For the second microstrip line, I want a negative voltage and the ground at the reference. It is a differential feeding. I am facing two problems. First, how can I define one as positive and one as a negative and the ground as a reference? Second, the two lines are near one another so I cannot define waveports ports based on the HFSS criteria that is the port width should be at least 10 times and height at least 8 times.
If i defined it based on the above criteria the two ports overlap with one another. If you recommend lumped port for this case then how can we introduce these polarities? The positive voltage on one port and a negative voltage on the other port. I had already tried lumped port technique.
Order By: Standard Newest Votes. Peter Serano posted this 15 December - Last edited 15 December Use lumped ports and draw the integration lines for the two ports in opposite directions.The HFSS Antenna course explores antenna-related HFSS topics such as radiating boundaries, including how well they absorb energy from different angles, and hybrid regions which connect different antenna simulations together.
HFSS Antenna covers both finite element analysis FEA volumetric simulation as well as integral equation IE simulation and how they can connect a reflector antenna dish simulation to a horn antenna simulation feeding the dish. HFSS Antenna practices impedance matching antenna with circuit elements and explores examples of finite array design analysis with unit cells and Floquet modes.
Following completion of this course, you will be able to:. Target Audience: Antenna Design Engineers. Teaching Method: Lecture modules and simulation workshops to gain hands-on knowledge. A training certificate is provided to all attendees who complete the course. Although the course listing is instructor led, the simulation workshops are self-explanatory and easy to follow for independent learners.
If there is no active public schedule available, private training can be arranged. Please contact us. Antenna geometry construction and synthesis from the Antenna Toolkit. Wave port, lumped port, and Floquet port excitations setup. Solution setup and Post-processing. Dynamic link antenna and circuit simulation.
Optimetrics — parameteric sweep and derivative tuning. Unit Cell Analysis Infinite Array. This is a 1. For virtual training, this course is covered over 4 x 2 hour sessions.
Module 1 Introductory workshops provide antenna-related HFSS familiarity; they should be completed independently prior to the start of class. Post-processing: far field plots, infinite sphere setup, S-parameter and fields plots. Dynamic link to RF circuit hierarchically driving an EM antenna structure. Introduction to Optimetrics. Parametric, Optimization, Statistical, Sensitivity Analysis.
Analytic Derivatives. Infinite Array,Unit Cell, and Floquet ports. Sorry, no classes were found that matched your country selection. Subscribe today to take online courses.
Please try again or Subscribe today to take online courses. Learning Outcome Following completion of this course, you will be able to: Create antennas from the Antenna Design Toolkit or by drawing new geometry Create antenna simulation results reports and plot field overlays on antenna geometry Connect antenna structures to RF circuit schematics Run Optimetrics Distinguish various EM formulations available for antenna design Set up both infinite array and finite array simulations Prerequisites Completion of the HFSS Getting Started course or equivalent familiarity with HFSS 3D modeler, workflow, solver setup, and post-processing plotting results graphs.
Knowledge of microwave electronic principles including S-parameters, transmission lines and antenna far-field radiation patterns. Knowledge of antenna impedance matching, infinite array and finite array principles are also important as workshop exercises utilize these engineering principles. Please try again.
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OK Learn More. Discussion Forum. Forum Home. New Discussion. Lumped Ports Confusion -- What are they supposed to be? Send Private Message Flag post as spam. Please login with a confirmed email address before reporting spam. Send a report to the moderators. How are lumped ports actually solved in the simulation? And what, physically, are they supposed to represent when applied in the Magnetic Fields interface? I would like to use lumped ports to excite my structures because ports in COMSOL allow for the computation of impedances and S-parameters, but the ports never behave as I'd expect them to.
The documentation states that a lumped port "applies a uniform electric field between two metallic boundaries" and that "the excitation at the port can be expressed as a voltage or as a current, or via the connection to a circuit interface. I would expect a current-exciting port to drive the specified amount of current through the attached conductor, but this appears to NOT be the case.
This means the "terminal current" you specify for the port does not actually specify the current excited by that port. So what does "terminal current" actually specify? I'd expect the dimensions of this block to match the dimensions of the port in some way, but, again, that is not the case.
As explained in the manual, the port represents a connection to a transmission line, with the two metallic boundaries constituting the conductors of the transmission line. Physically, for a Current excitation, the port applies a Surface Current Density on the boundary, the magnitude and direction of which depend on the port geometry. In the case of a Uniform port, the boundary must be rectangular, with two opposite sides touching metal boundaries.Remember Me? Re: integration line in HFSS If you search the site, you will find many previous posts on this subject.
Below is a response I posted at the time: The integration line is used to extract the impedance for a given waveguide cross section. The Zpi default uses the initial power, 1Watt, and the enclosed current, I, to determine the impedance.
The enclosed current is determined by the line integral of H around the periphery of the wave port as it is a PEC boundary so no integration line is required. The Zpv uses the integration line that is defined to integrate E upon, and it is best to define this line in the path of expected highest potential. As the line integral of E is the voltage, Zpv uses the initial power, 1Watt, and the voltage, as determined from the integration of E along the path defined by the integration line.
Zvi determines Z using the voltage and the enclosed current. The integration line also serves to set the initial phase polarization of the modes. Have Fun. HFSS waveport integration line 3. Part and Inventory Search. Welcome to EDABoard. Design Resources.
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Top Experience Points. EE World Online. Design Fast. The time now is All rights reserved.I was trying to simulate a device on HFSS which involves some lumped components. I drew rectangles where the lumped component is supposed to connect one metal to another. I assigned the rectangles with the lumped RLC boundary condition. I got the resonant frequency of my device with lumped components. I wanted to export the whole setup to ADS. So, I replaced the lumped RLC boundary condition with lumped ports excitation.
I simulated the same structure simply by replacing the lumped RLCs with lumped ports. The snp file of the device was exported to ADS. I replaced the lumped ports with actual lumped components on ADS. I used the same values for the lumped components as in the lumped RLCs. However, I see a significant variation in the resonant frequency of the device when simulated on ADS.
It shifts from 2 GHz to 2. After importing the HFSS model into Circuit - you may also find it useful to enable differential ports to help visualize and ensure the connections are correct. Pin Locations'. Then in the drop down menu, select 'Add individual reference pin per port'. I am still curious to know why there is a difference in the results between the case with lumped RLCs and lumped ports. I set up the lumped ports by using rectangular sheets.
The long one is a resistor and the short one is a capacitor. I am curious about this because I do not think it is the problem with ADS. I suspect that this difference in the results come from the HFSS simulations itself.
The main problem is that lumped ports simulation on HFSS will not generate any meaningful results that we can analyse. The results can only be verified after importing the snp files to a circuit simulator.
How are the ports contacting the structure? They appear to be overlapping? They are touching the surface of the adjacent metal.HFSS wave port.
I want to assign wave port exciatition to the signal inputtrace. I followed the HFSS guidelines of assigning a wave port by creating aport box and drawing integration line between ground and signal.HFSS 2.4GHz microstrip antenna by jayendra kumar
But I amgetting a strange error" Port refinement, process hf3d error: Port WavePort1 is assigned to aninternal face. Only allowed with lumped ports". I am not able to understand what this error means. Any advice on what thismeans and how to assign wave ports?
Thank you,JaganPS: The project simulates well with lumped ports. But want to compareresults with wave ports too. The best answer You can select the best answer for current question! Answered by jaganvaidyanathan 9 years 1 month 28 days. Yes works perfect. Thank you Jason.
Integration Line Hfss
I intended to write "creating a port face" not a box. Answered by jason. The wave port is within FSP the spherical air solid. If this is removed I see the port solution complete. Thank you all for the reply. Jason - My bad. AndI have defined the wave port on the model bounday touching the face of mysignal and ground. I have attached my project file here.
Lumped RLCs vs. Lumped ports in HFSS - substantial difference in the results
You can see the port face defined andthe integration line drawn from signal bottom to signal top. Please let meknow if am missing something in my port definitionThank you for the time. Answered by szinck1 9 years 1 month 28 days. Hi Jagan,Is the port placed inside the model? Best regards,SteveStephen P. The wave port should be located on the face or boundary of the HFSS problem.
Answered by baqar 9 years 1 month 28 days. First time posting, just wanted to test to make sure it was working. Answered by weirsi 9 years 1 month 29 days.
Consider, for example, a coaxial splitter as shown herewhich splits the signal from one coaxial cable coax equally into two. We know that the electromagnetic fields in the incoming and outgoing cables will have a certain form and that the energy is propagating in the direction normal to the cross section of the coax.
There are many other such cases where we know the form but not the magnitude or phase of the electromagnetic fields at some boundaries of our modeling domain. These situations call for the use of the Lumped Port and the Port boundary conditions.
Let us look at what these boundary conditions mean and when they should be used. We can begin our discussion of the Lumped Port boundary condition by looking at the fields in a coaxial cable.
[SI-LIST] Re: HFSS wave port
A coaxial cable is a waveguide composed of an inner and outer conductor with a dielectric in between. Over its range of operating frequencies, a coax operates in Tranverse Electro-Magnetic TEM mode, meaning that the electric and the magnetic field vectors have no component in the direction of wave propagation along the cable. That is, the electric and magnetic fields both lie entirely in the cross-sectional plane.
However, there also exists an analytic solution for this problem. So, since we know the shape of the electric field at the cross section of a coax, we can apply this as a boundary condition using the Lumped Port, Coaxial boundary condition.
The excitation options for this condition are that the excitation can be specified in terms of a cable impedance along with an applied voltage and phase, in terms of the applied current, or as a connection to an externally defined circuit. The electric field in a coaxial cable. For a coaxial cable, we always need to apply the boundary condition at an annular face, but we can also use the Lumped Port boundary condition in other cases.
The Uniform option can be used if you have a geometry as shown below: a surface bridging the gap between two electrically conductive faces. The electric field is assumed to be uniform in magnitude between the bounding faces, and the software automatically computes the height and width of the Lumped Port face, which should always be much smaller than the wavelength in the surrounding material.
Uniform Lumped Ports are commonly used to excite striplines and coplanar waveguides, as discussed in detail here. A typical Uniform Lumped Port geometry. The User-Defined option allows you to manually enter the height and width of the feed, as well as the direction of the electric field vector. This option is appropriate if you need to manually enter these settings, like in the geometry shown below and as demonstrated in this example of a dipole antenna.
An example of a User-Defined Lumped Port geometry. Another use of the Lumped Port condition is to model a small electrical element such as a resistor, capacitor, or inductor bonded onto a microwave circuit. The Lumped Port can be used to specify an effective impedance between two conductive boundaries within the modeling domain. There is an additional Lumped Element boundary condition that is identical in formulation to the Lumped Port, but has a customized user interface and different postprocessing options.
The example of a Wilkinson power divider demonstrates this functionality. The impedance can be computed for TEM mode waveguides only.
It is also possible to compute an approximate impedance for a structure that is very nearly TEM, as shown here. But once there is a significant electric or magnetic field in the direction of propagation, then we can no longer use the Lumped Port condition. Instead, we must use the Port boundary condition.
Again, there are analytic solutions for propagating fields in waveguide. These solutions are classified as either Transverse Electric TE or Transverse Magnetic TMmeaning there is no electric or magnetic field in the direction of propagation, respectively. The geometry we will consider is of two straight sections of different cross-sectional area. At the operating frequency, the wider section supports both TE10 and TE20 modes, while the narrower supports only the TE10 mode.
The waveguide is excited with a TE10 mode on the wider section.